来自解磊的问题
已知实数a,b,c满足abc=-1,a+b+c=4,aa2−3a−1+bb2−3b−1+cc2−3c−1=49,则a2+b2+c2=______.
已知实数a,b,c满足abc=-1,a+b+c=4,aa2−3a−1+bb2−3b−1+cc2−3c−1=49,则a2+b2+c2=______.
1回答
2020-07-15 21:18
已知实数a,b,c满足abc=-1,a+b+c=4,aa2−3a−1+bb2−3b−1+cc2−3c−1=49,则a2+b2+c2=______.
已知实数a,b,c满足abc=-1,a+b+c=4,aa2−3a−1+bb2−3b−1+cc2−3c−1=49,则a2+b2+c2=______.
∵abc=-1,a+b+c=4,∴a2-3a-1=a2-3a+abc=a(bc+a-3)=a(bc-b-c+1)=a(b-1)(c-1),∴aa2−3a−1=1(b−1)(c−1),同理可得:bb2−3b−1 =1(a−1)(c−1),cc2−3c−1=1(a−1)(b−1),又aa2−3a−1+bb2−3b−...