来自李立群的问题
两个完全相同的矩形纸片ABCD、BFDE如图放置，AB=BF．求证：四边形BNDM为菱形．
两个完全相同的矩形纸片ABCD、BFDE如图放置，AB=BF．
求证：四边形BNDM为菱形．
1回答
2020-07-18 00:28
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崔黎黎
证明：∵两个完全相同的矩形纸片ABCD、BFDE，根据矩形的对边平行，
∴BC∥AD，BE∥DF，
∴四边形BNDM是平行四边形，
∵∠ABM+∠MBN=90°，∠MBN+∠FBN=90°，
∴∠ABM=∠FBN．
在△ABM和△FBN中，
∠ABM＝∠FBNAB＝BF∠A＝∠BFN＝90°
2020-07-18 00:30:28
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