来自沈医文的问题
将函数y=sin(x+α)+sin(x+β)化为y=Asin(ωx+φ)(A>0,ω>0)的形式后,振幅为1,则α-β=___.
将函数y=sin(x+α)+sin(x+β)化为y=Asin(ωx+φ)(A>0,ω>0)的形式后,振幅为1,则α-β=___.
1回答
2020-07-17 21:46
将函数y=sin(x+α)+sin(x+β)化为y=Asin(ωx+φ)(A>0,ω>0)的形式后,振幅为1,则α-β=___.
将函数y=sin(x+α)+sin(x+β)化为y=Asin(ωx+φ)(A>0,ω>0)的形式后,振幅为1,则α-β=___.
函数y=sin(x+α)+sin(x+β)
=(sinxcosα+cosxsinα)+(sinxcosβ+cosxsinβ)
=sinx(cosα+cosβ)+cosx(sinα+sinβ),
化为y=Asin(ωx+φ)(A>0,ω>0)后,振幅为1,
∴(cosα+cosβ)2+(sinα+sinβ)2
=cos2α+2cosαcosβ+cos2β+sin2α+2sinαsinβ+sin2β
=2+2cos(α-β)=1,
∴cos(α-β)=-12