来自丁成的问题
ln(e^i)=(A.i(1+2kπ)(k∈Z)B.2kπ*i(k∈Z)C.i(1+kπ)(k∈Z)D.π*i
ln(e^i)=(
A.i(1+2kπ)(k∈Z)
B.2kπ*i(k∈Z)
C.i(1+kπ)(k∈Z)
D.π*i
1回答
2020-07-31 21:09
ln(e^i)=(A.i(1+2kπ)(k∈Z)B.2kπ*i(k∈Z)C.i(1+kπ)(k∈Z)D.π*i
ln(e^i)=(
A.i(1+2kπ)(k∈Z)
B.2kπ*i(k∈Z)
C.i(1+kπ)(k∈Z)
D.π*i
A