来自崔少辉的问题
(x-2)^2+(x-1)^2+x^2=(x+1)^2+(x+2)^2一元二次方程,
(x-2)^2+(x-1)^2+x^2=(x+1)^2+(x+2)^2一元二次方程,
1回答
2020-08-02 19:54
(x-2)^2+(x-1)^2+x^2=(x+1)^2+(x+2)^2一元二次方程,
(x-2)^2+(x-1)^2+x^2=(x+1)^2+(x+2)^2一元二次方程,
由(x-2)^2+(x-1)^2+x^2=(x+1)^2+(x+2)^2得
x²-4x+4+x²-2x+1+x²=x²+2x+1+x²+4x+4
3x²-6x+5=2x²+4x+5
x²-10x=0
x(x-10)=0
x1=0x2=10