来自邱义芬的问题
因式分解:(x-根号2)=根号5*X(2-根号2*x
因式分解:(x-根号2)=根号5*X(2-根号2*x
1回答
2020-09-03 23:30
因式分解:(x-根号2)=根号5*X(2-根号2*x
因式分解:(x-根号2)=根号5*X(2-根号2*x
(x-根号2)=根号5*X(2-根号2*x)
(x-根号2)-根号5*X(2-根号2*x)=0
(x-根号2)-根号5*X*√2(√2-x)=0
(x-√2)(1+√10x)=0
x-√2=0或1+√10x=0
即x1=√2,x2=-√10/10