来自宋帅的问题
计算:(1)a+2a−2•1a2+2a;(2)x2−2x+1x2−1÷x−1x2+x;(3)(a2−4a2−4a+4−1a−2)÷a+1a+2;(4)1−(a−11−a)÷a2−a+1a2−2a+1;(5)(−1)2+(12)−1−5÷(2004−π)0;(6)(a2b)2•(b2−a)3•(−ba)−4;(
计算:
(1)a+2a−2•1a2+2a;
(2)x2−2x+1x2−1÷x−1x2+x;
(3)(a2−4a2−4a+4−1a−2)÷a+1a+2;
(4)1−(a−11−a)÷a2−a+1a2−2a+1;
(5)(−1)2+(12)−1−5÷(2004−π)0;
(6)(1a2+2a0)2•(1a2+2a1)3•(−1a2+2a2)−4;
(7)(1a2+2a3−1a2+2a4)•1a2+2a5;
(8)1a2+2a6+1a2+2a7.
1回答
2020-09-08 22:10