【分解因式.及化简求值.①(8m^3)-1②(x^3n)+1-查字典问答网
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  【分解因式.及化简求值.①(8m^3)-1②(x^3n)+1③(a^3m)-a^(3m+3)④(a+b)^3-(a-b)^3⑤(x+y)^4(x-y)-(y+x)(y-x)^4⑥(x+1)(x^2-x+1)-1-y^3⑦(-27a^3)+64b^3⑧(x^4)-(x^2)+8x-16⑨(x^4)-(4x^2)+3⑩(a^8)+(a^4)-211.(9x^4)-(13x^2×y^2)+4y^412.x^(n+5)-】

  分解因式.及化简求值.

  ①(8m^3)-1

  ②(x^3n)+1

  ③(a^3m)-a^(3m+3)

  ④(a+b)^3-(a-b)^3

  ⑤(x+y)^4(x-y)-(y+x)(y-x)^4

  ⑥(x+1)(x^2-x+1)-1-y^3

  ⑦(-27a^3)+64b^3

  ⑧(x^4)-(x^2)+8x-16

  ⑨(x^4)-(4x^2)+3

  ⑩(a^8)+(a^4)-2

  11.(9x^4)-(13x^2×y^2)+4y^4

  12.x^(n+5)-7x^(n+3)-8x^(n+1)

  13.已知(a^2)+a+1=0,求(a^3)+(2a^2)+2a+3的值.

  14.如果a+b=1,求(a^3)+3ab+b^3的值.

  15.如果(a^2)+5a+k分解后有一个因式为(a-1),那么k的值为多少?

1回答
2020-09-09 23:51
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李正荣

  题目真多!还是把做完了,累倒不累,就是眼花得厉害!

  ①立方差公式:a^3-b^3=(a-b)(a^2+ab+b^2)此题a=2m,b=1

  (8m^3)-1=(2m-1)(4m^2+2m+1)

  ②立方和公式:a^3+b^3=(a+b)(a^2-ab+b^2)此题a=x^n,b=1

  (x^3n)+1=(x^n+1)(x^2n-x^n+1)

  ③提公因式a^3m

  (a^3m)-a^(3m+3)=a^3m(1-a)(1+a+a^2)

  ④(a+b)^3-(a-b)^3

  [(a+b)-(a-b)][(a+b)^2+(a+b)(a-b)+(a-b)^2]

  =2b[a^2+2ab+b^2+a^2-b^2+a^2-2ab+b^2]

  =2b(3a^2+b^2)

  =6a^2b+2b^3

  ⑤提公因式(x+y)(x-y)

  (x+y)^4(x-y)-(y+x)(y-x)^4

  =(x+y)(x-y)[(x+y)^3+(x-y)^3]

  =(x+y)(x-y){[(x+y)+(x-y)][(x+y)^2-(x+y)(x-y)+(x-y)^2]}

  =2x(x+y)(x-y)(x^2-3y^2)

  ⑥(x+1)(x^2-x+1)-1-y^3

  =x^3+1-1-y^3

  =x^3-y^3

  =(x-y)(x^2+xy+y^2)

  ⑦(-27a^3)+64b^3

  =(4b)^3-(3a)^3

  =(4b-3a)(16b^2+12ab+9a^2)

  ⑧题错,改为:

  (x^4)-(4x^2)+8x-16

  =x^4-4x^2+8x-16

  =x^2(x^2-4)+8(x-2)

  =x^2(x+2)(x-2)+8(x-2)

  =(x-2)[x^2(x+2)+8]

  =(x-2)(x^3+2x^2+8)

  ⑨(x^4)-(4x^2)+3

  =(x^2-1)(x^2-3)

  =(x+1)(x-1)(x+√3)(x-√3)

  ⑩(a^8)+(a^4)-2

  =(a^4-1)(a^4+2)

  =(a^2-1)(a^2+1)(a^4+2)

  =(a+1)(a-1)(a^2+1)(a^4+2)

  11.(9x^4)-(13x^2×y^2)+4y^4

  =(x^2-y^2)(9x^2-4y^2)

  =(x-y)(x+y)(3x-y)(3x+y)

  12.x^(n+5)-7x^(n+3)-8x^(n+1)

  =x^(n+1)(x^4-7x^2-8)

  =x^(n+1)(x^2+1)(x^2-8)

  =x^(n+1)(x^2+1)(x+2√2)(x-2√2)

  13.已知(a^2)+a+1=0,求(a^3)+(2a^2)+2a+3的值.

  原式=(a^2+a+1)(a+1)+2

  =2

  14.如果a+b=1,求(a^3)+3ab+b^3的值.

  原式=(a^3+b^3)+3ab

  =(a+b)(a^2+b^2-ab)+3ab

  =a^2+b^2+2ab

  =(a+b)^2

  =1

  15.如果(a^2)+5a+k分解后有一个因式为(a-1),那么k的值为多少?

  设(a-1)(a+m)=a^2+5a+k则

  -1m=k

  m-1=5

  解得m=6,k=-6

2020-09-09 23:54:31

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