先化简,再求值(1)(3x-3)/(x^2-1)÷3x/(x-查字典问答网
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来自顾玲娟的问题

  先化简,再求值(1)(3x-3)/(x^2-1)÷3x/(x+1)-1/(x-1),其中x=2(2)(x^2+2x+1)/(x+2)÷(x^2-1)/(x-1)-1/(x+2),其中x=1/2

  先化简,再求值(1)(3x-3)/(x^2-1)÷3x/(x+1)-1/(x-1),其中x=2

  (2)(x^2+2x+1)/(x+2)÷(x^2-1)/(x-1)-1/(x+2),其中x=1/2

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2020-09-15 21:58
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丁红涛

  (3x-3)/(x^2-1)÷3x/(x+1)-1/(x-1)=3(x-1)/(x+1)(x-1)*(x+1)/3x-1/(x-1)=1/x-1/(x-1)=(x-1-x)/x(x-1)=1/x(1-x)=1/[2*(-1)=-1/2(x^2+2x+1)/(x+2)÷(x^2-1)/(x-1)-1/(x+2)=(x+1)^2/(x+2)*(x-1)/(x+1)(x-1)-1/(x+2)=(...

2020-09-15 22:00:33

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