来自戴国宪的问题
【(2)(x-2)(x+2)-(x+1)(x-3)(3)(ab+1)²-(ab-1)²(4)(2x-y)²-4(x-y)(x+2y)】
(2)(x-2)(x+2)-(x+1)(x-3)
(3)(ab+1)²-(ab-1)²
(4)(2x-y)²-4(x-y)(x+2y)
1回答
2020-09-21 01:03
【(2)(x-2)(x+2)-(x+1)(x-3)(3)(ab+1)²-(ab-1)²(4)(2x-y)²-4(x-y)(x+2y)】
(2)(x-2)(x+2)-(x+1)(x-3)
(3)(ab+1)²-(ab-1)²
(4)(2x-y)²-4(x-y)(x+2y)
(2)(x-2)(x+2)-(x+1)(x-3)
=x²-4-(x²-2x-3)
=x²-4-x²+2x+3
=2x-1
(3)(ab+1)²-(ab-1)²
=(ab+1+ab-1)(ab+1-ab+1)
=2(2ab)
=4ab
(4)(2x-y)²-4(x-y)(x+2y)
=4x²-4xy+y²-4(x²+xy-2y²)
=4x²-4xy+y²-4x²-4xy+8y²
=-8xy+9y²