来自龚怿的问题
因式分解(1)x2-2x-8(2)x2(x-1)-4(1-x)2.
因式分解
(1)x2-2x-8
(2)x2(x-1)-4(1-x)2.
1回答
2020-09-22 14:25
因式分解(1)x2-2x-8(2)x2(x-1)-4(1-x)2.
因式分解
(1)x2-2x-8
(2)x2(x-1)-4(1-x)2.
(1)x2-2x-8=(x-4)(x+2);
(2)x2(x-1)-4(1-x)2
=(x-1)[x2-4(x-1)
=(x-1)[x2-4x+4)
=(x-1)(x-2)2.