(1)1-1/6+1/42+1/56+1/72+1/90(2-查字典问答网
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来自胡光华的问题

  (1)1-1/6+1/42+1/56+1/72+1/90(2)5/4-9/20+11/30-13/42+15/56-17/72+19/90(3)1/3+3/4+2/5+5/7+7/8+9/20+10/21+11/24+12/35

  (1)1-1/6+1/42+1/56+1/72+1/90

  (2)5/4-9/20+11/30-13/42+15/56-17/72+19/90

  (3)1/3+3/4+2/5+5/7+7/8+9/20+10/21+11/24+12/35

1回答
2020-09-23 10:44
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姜学军

  1)1-1/6+1/42+1/56+1/72+1/90

  =5/6+1/42+1/56+1/72+1/90

  =6/7+1/56+1/72+1/90

  =49/56+1/72+1/90

  =7/8+1/72+1/90

  =64/72+1/90

  =81/90

  =9/10

  (2)5/4-9/20+11/30-13/42+15/56-17/72+19/90

  =25/20-9/20+11/30-13/42+15/56-17/72+19/90

  =16/20+11/30-13/42+15/56-17/72+19/90

  =24/30+11/30-13/42+15/56-17/72+19/90

  =35/30-13/42+15/56-17/72+19/90

  =49/42-13/42+15/56-17/72+19/90

  =36/42+15/56-17/72+19/90

  =48/56+15/56-17/72+19/90

  =63/56-17/72+19/90

  =81/72-17/72+19/90

  =64/72+19/90

  =8/9+19/90

  =80/90+19/90

  =99/90

  =11/10

  (3)1/3+3/4+2/5+5/7+7/8+9/20+10/21+11/24+12/35

  =1/3+3/4+2/5+5/7+7/8+1/5+1/4+1/7+1/3+1/3+1/8+1/7+1/5

  =(1/3+1/3+1/3)+(3/4+1/4)+(2/5+1/5+1/5)+(5/7+1/7+1/7)+(7/8+1/8)

  =1+1+4/5+1+1

  =24/5=4.8

  1.前面两题的关键是两个数相加或相减后得到的数值约分后,刚好和后一个数字可以找到公约数

  2.后面一题经过观察发现后面的四个数字如:9/20可以分解为1/4+5/1,找到规律后就可以快速解题

2020-09-23 10:47:40

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