来自何建平的问题
观察:1/2×3=1/2-1/31/3×4=1/3-1/41/4×5=1/4-1/5计算:1/6+1/12+1/20+1/30+…1/2005×2006
观察:1/2×3=1/2-1/31/3×4=1/3-1/41/4×5=1/4-1/5计算:1/6+1/12+1/20+1/30+…1/2005×2006
1回答
2020-09-27 00:55
观察:1/2×3=1/2-1/31/3×4=1/3-1/41/4×5=1/4-1/5计算:1/6+1/12+1/20+1/30+…1/2005×2006
观察:1/2×3=1/2-1/31/3×4=1/3-1/41/4×5=1/4-1/5计算:1/6+1/12+1/20+1/30+…1/2005×2006
1/6+1/12+1/20+1/30+…1/2005×2006
=1/2-1/3+1/3-1/4+1/4-1/5………………+1/2005-1/2006(中间的全部抵消)
=1/2-1/2006
=1002/2006
=501/1003