来自纪兴权的问题
x^2+y^2-6x-8y+25=o求代数式(xy-3x^2)/y^2-xy-6x^2的值
x^2+y^2-6x-8y+25=o求代数式(xy-3x^2)/y^2-xy-6x^2的值
1回答
2020-09-26 23:37
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刘冀伟
(x-3)^2+(y-4)^2=0
x=3y=4
(xy-3x^2)/y^2-xy-6x^2
=[x(y-3x)]/[(y-3x)(y+2x)}
=x/[y+2x]
=3/[4+2*3]
=3/10
2020-09-26 23:38:41