来自任殿义的问题
【先化简再求值[(3a-7)^2-(a+5)^2](4a-24)其中a=0.02】
先化简再求值[(3a-7)^2-(a+5)^2](4a-24)其中a=0.02
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2020-09-30 23:45
【先化简再求值[(3a-7)^2-(a+5)^2](4a-24)其中a=0.02】
先化简再求值[(3a-7)^2-(a+5)^2](4a-24)其中a=0.02
[(3a-7)^2-(a+5)^2](4a-24)
=[(3a-7+a+5)*(3a-7-a-5)]/(4a-24)
=(4a-2)*(2a-12)/(4a-24)
=(2a-1)(a-6)/(a-6)
=2a-1
=2×0.02-1
=0.04-1
=-0.96