Sn=1/[n(n+1)(n+2)]=(1/2){1/[n)n+1)]-1/[(n+1)(n+2)]}

　　=(1/2)[1/n-1/(n+1)-1/(n+1)+1/(n+2)]

　　=(1/2)[1/n-2/(n+1)+1/(n+2)]

　　=1/1x2x3+1/2x3x4+1/3x4x5+...+1x/n(n+1)(n+2)

　　=(1/2)[1/1-2/2+1/3+1/2-2/3+1/4+1/3-2/4+1/5+/4-2/5+1/6

　　+.+1/n-2/(n+1)+1/(n+2)]

　　=(1/2)[1-1/2-1/(n+1)+1/(n+2)]

　　=(n^2+3n)/[4(n+1)(n+2)]