来自刘铁铭的问题
mx平方-[2m-1]x+m-2=0【m大于0】的实数根为xa和xb且{xa-3][xb-3]=5m,求m值?
mx平方-[2m-1]x+m-2=0【m大于0】的实数根为xa和xb且{xa-3][xb-3]=5m,求m值?
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2020-10-13 07:20
mx平方-[2m-1]x+m-2=0【m大于0】的实数根为xa和xb且{xa-3][xb-3]=5m,求m值?
mx平方-[2m-1]x+m-2=0【m大于0】的实数根为xa和xb且{xa-3][xb-3]=5m,求m值?
mx-[2m-1]x+m-2=0【m大于0】的实数根为xa和xb所以:xa+xb=(2m-1)/mxaxb=(9m-2)/m又因:[xa-3][xb-3]=5mxaxb-3xa-3ab+9=5mxaxb-3(xa+xb)+9=5m即:(m-2)/m-3x(2m-1)/m+9=5mm-2-6m+3+9m=5m5m-4m-1=...