来自蔡伟华的问题
已知直线Ax+By+C=0(其中A*A+B*B=C*C,C≠0)与圆x*x+y*y=4交于M,N,O是坐标原点,则OM的向量乘ON的向量等于
已知直线Ax+By+C=0(其中A*A+B*B=C*C,C≠0)与圆x*x+y*y=4交于M,N,O是坐标原点,则OM的向量乘ON的向量等于
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2020-10-23 06:09
已知直线Ax+By+C=0(其中A*A+B*B=C*C,C≠0)与圆x*x+y*y=4交于M,N,O是坐标原点,则OM的向量乘ON的向量等于
已知直线Ax+By+C=0(其中A*A+B*B=C*C,C≠0)与圆x*x+y*y=4交于M,N,O是坐标原点,则OM的向量乘ON的向量等于
L:Ax+By+C=0(1)
A^2+B^2=C^2
C:x^2+y^2=4(2)
letM(x1,y1),N(x2,y2)
sub(1)into(2)
x^2+[(C-Ax)/B]^2=4
(1+(A/B)^2)x^2-(2AC/B)x+(C/B)^2-4=0
x1x2=[(C/B)^2-4]/(1+(A/B)^2)
=(C^2-4B^2)/(B^2+A^2)
=(C^2-4B^2)/(C^2)
=1-4(B/C)^2
Similary,wehave
((C-By)/A)^2+y^2=4
(1+(B/A)^2)y^2-(2BC/A)y+(C/A)^2-4=0
y1y2=[(C/A)^2-4]/(1+(B/A)^2)
=(C^2-4A^2)/(A^2+B^2)
=(C^2-4A^2)/(C^2)
=1-4(A/C)^2
OM.ON
=x1x2+y1y2
=1-4(B/C)^2+1-4(A/C)^2
=2-4(B^2+A^2)/C^2
=2-4
=-2