来自李晓鸥的问题
已知在1×105Pa,298K条件下,2mol氢气燃烧生成水蒸气放出484kJ热量,下列热化学方程式正确的是()A.H2O(g)=H2(g)+12O2(g)△H=+242kJ/molB.2H2(g)+O2(g)=2H2O(l)△H=-484kJ/mo
已知在1×105Pa,298K条件下,2mol氢气燃烧生成水蒸气放出484kJ热量,下列热化学方程式正确的是()
A.H2O ( g )=H2( g )+12O2( g )△H=+242 kJ/mol
B.2H2( g )+O2( g )=2H2O ( l )△H=-484 kJ/mol
C.H2( g )+12O2( g )=H2O ( g )△H=+242 kJ/mol
D.2H2( g )+O2( g )=2H2O ( g )△H=+484 kJ/mol
1回答
2020-10-24 14:59