来自洪佳琼的问题
【已知分解1g碳酸镁固体吸收1.366kJ,则它的热化学方程式是()A.MgCO3(s)═MgO(s)+CO2(g)△H=+1.366kJ/molB.MgCO3(s)═MgO(s)+CO2(g)△H=-1.366kJ/molC.MgCO3(s)═MgO(s)+CO2(g)△H=-】
已知分解1g碳酸镁固体吸收1.366kJ,则它的热化学方程式是()
A.MgCO3(s)═MgO(s)+CO2(g)△H=+1.366 kJ/mol
B.MgCO3(s)═MgO(s)+CO2(g)△H=-1.366 kJ/mol
C.MgCO3(s)═MgO(s)+CO2(g)△H=-114.7 kJ/mol
D.MgCO3(s)═MgO(s)+CO2(g)△H=+114.7 kJ/mol
1回答
2020-10-26 05:08