来自林德杰的问题
设y=ln1/x+ln2求y'
设y=ln1/x+ln2求y'
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2020-11-03 16:19
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两种方法：1.求ln1/x的导数时,结果是1/(1/x)=x,因为是复合函数,此时还要乘以1/x的导数,即-1/x^2,最后结果是-1/x,ln2是常数,导数是0所以y'=-1/x;2.如果你上面的方法理解不了,也可以用对数性质把ln1/x化简,ln1/x=-lnx;...
2020-11-03 16:24:35
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