来自倪德明的问题
已知集合A＝{x|(x－2)[x－(3a－1)]＜0},B＝{x|x－(a平方－1)分之x－2a＜0},其中a不等于1.当a＝2,求A交B
已知集合A＝{x|(x－2)[x－(3a－1)]＜0},B＝{x|x－(a平方－1)分之x－2a＜0},其中a不等于1.当a＝2,求A交B
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2020-11-08 04:49
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宋志伟
a=2
A＝{x|(x－2)[x－(3a－1)]＜0},A＝{x|(x－2)（x－5）＜0},则2
2020-11-08 04:54:36
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