来自沈承林的问题
当A,B,C满足（）时,直线AX+BY+C=0经过原点
当A,B,C满足（）时,直线AX+BY+C=0经过原点
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2020-11-13 01:54
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李泉溪
C=0,且AB≠0.
文字表示即：C等于零,且AB不同时为零.
2020-11-13 01:55:41
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