来自崔双喜的问题
因式分解:已知a+b=5,ab=3,求(a²-b²)²的值
因式分解:已知a+b=5,ab=3,求(a²-b²)²的值
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2020-11-17 16:16
因式分解:已知a+b=5,ab=3,求(a²-b²)²的值
因式分解:已知a+b=5,ab=3,求(a²-b²)²的值
(a-b)²
=a²+b²-2ab
=(a+b)²-4ab
=5²-4x3
=25-12
=13
(a²-b²)²
=(a+b)²(a-b)²
=25x13
=325