来自刘栋斌的问题
函数y=−x−1−−−−−√(x⩾1)的反函数为()。A.y=x2−1(x⩾1)B.y=x2+1(x⩾1)C.y=x2−1(x⩽0)D.y=x2+1(x⩽0)
函数y=−x−1−−−−−√(x⩾1)的反函数为( )。A.y=x2−1(x⩾1)B.y=x2+1(x⩾1)C.y=x2−1(x⩽0)D.y=x2+1(x⩽0)
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2019-08-31 19:14
函数y=−x−1−−−−−√(x⩾1)的反函数为()。A.y=x2−1(x⩾1)B.y=x2+1(x⩾1)C.y=x2−1(x⩽0)D.y=x2+1(x⩽0)
函数y=−x−1−−−−−√(x⩾1)的反函数为( )。A.y=x2−1(x⩾1)B.y=x2+1(x⩾1)C.y=x2−1(x⩽0)D.y=x2+1(x⩽0)
本题主要考查反函数。已知函数y=−x−1−−−−−√(x⩾1),则可得y⩽0,并且可把函数转化为x=y2+1。分别用x替换y,用y替换x,得反函数y=x2+1(x⩽0)。故本题正确答案为D。易错项分析:本题易错项为B。考生可能在