来自吕肖庆的问题
(根号3+根号2)^2log(根号下3-根号下2)^根号5=跪谢额```
(根号3+根号2)^2log(根号下3-根号下2)^根号5=跪谢额```
1回答
2020-12-09 04:14
(根号3+根号2)^2log(根号下3-根号下2)^根号5=跪谢额```
(根号3+根号2)^2log(根号下3-根号下2)^根号5=跪谢额```
(√3+√2)^[2log(√3-√2)(√5)]
=(√3-√2)^[log(√3-√2)(1/5)]
=1/5
√3+√2=(√3-√2)^(-1)
2log(√3-√2)(√5)=log(√3-√2)(5)
则原式=(√3-√2)^[-log(√3-√2)(5)]=(√3-√2)^[log(√3-√2)(1/5)=1/5
这里用到了公式a^[loga(x)]=x