来自吉培荣的问题
(tanx-sinx)/sin3x求极限怎么做?
(tanx-sinx)/sin3x求极限怎么做?
1回答
2020-12-21 02:40
(tanx-sinx)/sin3x求极限怎么做?
(tanx-sinx)/sin3x求极限怎么做?
解:原式=lim[tanx(1-cosx)/sin3x](x→0)之后用等价无穷小代换:当x→0时,有:tanx~x;1-cosx=2[sin(x/2)]^2~2×(x/2)^2=x^2/2;sin3x~3x;原式=lim[x(x^2/2)/3x](x→0)=lim(x^2/6)(x→0)...