曾经写过一个,你看看,你最好弄个实际需求,也好帮你

　　已知(a*7+b*9+c*10+d*5+222)%11=3,a,b,c,d都是0-9的整数,怎么用sql输出a,b,c,d的所有结果

　　declare @a int

　　declare @b int

　　declare @c int

　　declare @d int

　　declare @str int

　　set @str=0

　　while @str<=9999

　　begin

　　set @a=cast(substring(right('0000'+cast(cast(@str as varchar) as varchar),4),1,1) as int)

　　set @b=cast(substring(right('0000'+cast(cast(@str as varchar) as varchar),4),2,1) as int)

　　set @c=cast(substring(right('0000'+cast(cast(@str as varchar) as varchar),4),3,1) as int)

　　set @d=cast(substring(right('0000'+cast(cast(@str as varchar) as varchar),4),4,1) as int)

　　if (@a*7+@b*9+@c*10+@d*5+222)%11=3

　　begin

　　print ('a='+cast(@a as varchar)+' b='+cast(@b as varchar)+' c='+cast(@c as varchar)+' d='+cast(@d as varchar))

　　end

　　set @str=@str+1

　　end

　　sqlserver中直接运行即可,mysql的你也就照着改一下吧