来自何巍的问题
等差数列{an},{bn}的前n项和分别为Sn,Tn,若SnTn=2n3n+1,则anbn=()A.23B.2n−13n−1C.2n+13n+1D.2n−13n+4
等差数列{an},{bn}的前n项和分别为Sn,Tn,若SnTn=2n3n+1,则anbn=()
A.23
B.2n−13n−1
C.2n+13n+1
D.2n−13n+4
1回答
2020-12-28 21:54