来自安岩的问题
1.已知:a,b是正数,求证:a+b≥2根号下ab2.已知x=2,y=二分之一,求根号x-根号下y分之根号x+根号下y-根号下x+根号下y分之根号x-根号下y.
1.已知:a,b是正数,求证:a+b≥2根号下ab
2.已知x=2,y=二分之一,求根号x-根号下y分之根号x+根号下y-根号下x+根号下y分之根号x-根号下y.
3回答
2020-01-16 18:44