来自万玉霞的问题
【(1/a-b-1/a+b)/[b/(a^2-2ab+b^2)](因式分解)化简】
(1/a-b-1/a+b)/[b/(a^2-2ab+b^2)](因式分解)化简
1回答
2020-01-16 13:19
【(1/a-b-1/a+b)/[b/(a^2-2ab+b^2)](因式分解)化简】
(1/a-b-1/a+b)/[b/(a^2-2ab+b^2)](因式分解)化简
(1/a-b-1/a+b)/[b/(a^2-2ab+b^2)]=[2b/(a+b)(a-b)]/[b/(a-b)^2=[2b/(a+b)(a-b)]*(a-b)^2/b=2(a-b)/(a+b)
满意请采纳