来自贾宏的问题
【(1)计算:(3)2−16+3−8.(2)分解因式:a2-4(a-b)2.(3)计算:1−x−yx+2y÷x2−y2x2+4xy+4y2.(4)化简求值:(3x+2)(3x-2)-5x(x+1)-(2x-1)2,其中x=−13.(5)解方程:6x−1+3x=x+5x2−x】
(1)计算:(
3)2−
16+3−8
.
(2)分解因式:a2-4(a-b)2.
(3)计算:1−x−yx+2y÷x2−y2x2+4xy+4y2.
(4)化简求值:(3x+2)(3x-2)-5x(x+1)-(2x-1)2,其中x=−13.
(5)解方程:6x−1+3x=x+5x2−x
1回答
2020-01-16 23:55