来自都东的问题
请问x3+3px2+(3p2-q2)x+p(p2-q2)分解因式(p为参数)
请问x3+3px2+(3p2-q2)x+p(p2-q2)分解因式(p为参数)
1回答
2020-01-17 00:17
请问x3+3px2+(3p2-q2)x+p(p2-q2)分解因式(p为参数)
请问x3+3px2+(3p2-q2)x+p(p2-q2)分解因式(p为参数)
化简为x3+3px2+3xp2+p3-q2x-pq2
=(x+p)3-(x+p)q2
=(x+p)[(x+p)2-q2]
=(x+p)(x+p+q)(x+p-q)