来自高雪强的问题
高一数学三角函数化简为题√[(sin^2α)(1+cotα)+(cos^2α)(1+tanα)]
高一数学三角函数化简为题
√[(sin^2α)(1+cotα)+(cos^2α)(1+tanα)]
1回答
2020-01-29 23:14
高一数学三角函数化简为题√[(sin^2α)(1+cotα)+(cos^2α)(1+tanα)]
高一数学三角函数化简为题
√[(sin^2α)(1+cotα)+(cos^2α)(1+tanα)]
√[(sin^2α)(1+cotα)+(cos^2α)(1+tanα)]
=√[(sin)^2+sinacosa+sinacosa+(cosa)^2]
=√(sina+cosa)^2
=|sina+cosa|