来自商桂芝的问题
设tanα=12,则sinα+2cosαsinα−cosα=______.
设tanα=12,则sinα+2cosαsinα−cosα=______.
1回答
2020-01-29 22:12
设tanα=12,则sinα+2cosαsinα−cosα=______.
设tanα=12,则sinα+2cosαsinα−cosα=______.
∵tanα=12