来自汤红吉的问题
先化简,再求值:x2−xx+1•x2−1x2−2x+1,其中x满足x2-3x+2=0.
先化简,再求值:x2−xx+1•x2−1x2−2x+1,其中x满足x2-3x+2=0.
1回答
2020-01-31 20:59
先化简,再求值:x2−xx+1•x2−1x2−2x+1,其中x满足x2-3x+2=0.
先化简,再求值:x2−xx+1•x2−1x2−2x+1,其中x满足x2-3x+2=0.
原式=x(x−1)x+1•(x+1)(x−1)(x−1)