来自田英明的问题
先化简,再求值:(1a+2−1)÷a2−1a+2,其中a=2.
先化简,再求值:(1a+2−1)÷a2−1a+2,其中a=2.
1回答
2020-02-01 00:59
先化简,再求值:(1a+2−1)÷a2−1a+2,其中a=2.
先化简,再求值:(1a+2−1)÷a2−1a+2,其中a=2.
原式=−(a+1)a+2÷(a+1)(a−1)a+2