来自程宏辉的问题
【化简求值:(x-4)/(x^2-1)÷(x^2-3x-4)/(x^2+2x+1)+1/(x-1),其中x=2倍根号3+1】
化简求值:
(x-4)/(x^2-1)÷(x^2-3x-4)/(x^2+2x+1)+1/(x-1),其中x=2倍根号3+1
1回答
2020-01-31 10:47
【化简求值:(x-4)/(x^2-1)÷(x^2-3x-4)/(x^2+2x+1)+1/(x-1),其中x=2倍根号3+1】
化简求值:
(x-4)/(x^2-1)÷(x^2-3x-4)/(x^2+2x+1)+1/(x-1),其中x=2倍根号3+1
(x-4)/(x^2-1)÷(x^2-3x-4)/(x^2+2x+1)+1/(x-1)
=2/(x-1),
将x=2倍根号3+1代入有
(x-4)/(x^2-1)÷(x^2-3x-4)/(x^2+2x+1)+1/(x-1)
=(根号3)/3