来自耿文东的问题
求值:arctan1/2+arctan1/3
求值:arctan1/2+arctan1/3
1回答
2020-01-31 14:06
求值:arctan1/2+arctan1/3
求值:arctan1/2+arctan1/3
分析:原题可化为已知:tanx=1/2,tany=1/3,x,y∈(-π/2,π/2)(反正切函数定义).求x+y的值.由题意,tan(x+y)=(tanx+tany)/(1-tanxtany)=(1/2+1/3)/(1-1/2×1/3)=1因为tanx,tany均大于0,又x,y∈(-π/2,π/...