来自欧阳伶俐的问题
已知x(x-1)-(x2-y)=-2,求x2+y22−xy的值.
已知x(x-1)-(x2-y)=-2,求x2+y22−xy的值.
1回答
2020-01-31 14:31
已知x(x-1)-(x2-y)=-2,求x2+y22−xy的值.
已知x(x-1)-(x2-y)=-2,求x2+y22−xy的值.
∵x(x-1)-(x2-y)=-2,
∴x2-x-x2+y=-2,
∴x-y=2,
∴x