来自那丽春的问题
【设xyz=1,求x/(xy+x+1)+y/(yz+y+1)+z/(zx+z+1)的值已知实数a满足a^2+4a-8=0,求1/(a+1)-(a+3)/(a^2-1)×(a^2-2a+1)/(a^2+6a+9)的值】
设xyz=1,求x/(xy+x+1)+y/(yz+y+1)+z/(zx+z+1)的值
已知实数a满足a^2+4a-8=0,求1/(a+1)-(a+3)/(a^2-1)×(a^2-2a+1)/(a^2+6a+9)的值
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2020-02-07 00:43