来自段胜利的问题
已知集合{b}={x∈R|ax2-4x+1=0,a,b∈R}则a+b=()A.0或1B.92C.14D.14或92
已知集合{b}={x∈R|ax2-4x+1=0,a,b∈R}则a+b=()
A.0或1
B.92
C.14
D.14或92
1回答
2020-02-08 22:33
已知集合{b}={x∈R|ax2-4x+1=0,a,b∈R}则a+b=()A.0或1B.92C.14D.14或92
已知集合{b}={x∈R|ax2-4x+1=0,a,b∈R}则a+b=()
A.0或1
B.92
C.14
D.14或92
∵集合{b}={x∈R|ax2-4x+1=0,a,b∈R},
∴a=0,或△=16-4a=0.
当a=0时,{b}={x|-4x+1=0}={14