f(x)=ax^2+2ln(1-x)f'(x)=2ax+2/(1-x)*(1-x)'=2ax+2/(x-1)∵f(x)在[-3,-1]上是增函数∴任意的x∈[-3,-1],f'(x)≥0恒成立即2ax+2/(x-1)≥0,ax≥1/(1-x),a≤1/(x-x²)恒成立需a≤[1/(x-x²)]min∵x-x²...

　　确定答案是对的吗？