来自柳萍的问题
(1)计算:27+2−8−12;(2)解方程:x2-4x-3=0.
(1)计算:
27+
2−
8−
12;
(2)解方程:x2-4x-3=0.
1回答
2020-02-27 07:04
(1)计算:27+2−8−12;(2)解方程:x2-4x-3=0.
(1)计算:
27+
2−
8−
12;
(2)解方程:x2-4x-3=0.
(1)原式=3
3