(cosπ/12+sin11π/12)(cosπ/12+si-查字典问答网
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来自鲍晓慧的问题

  (cosπ/12+sin11π/12)(cosπ/12+sin13π/12)

  (cosπ/12+sin11π/12)(cosπ/12+sin13π/12)

1回答
2020-03-04 20:31
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陈伟强

  (cosπ/12+sin11π/12)(cosπ/12+sin13π/12)

  =(cosπ/12+sin1π/12)(cosπ/12-sin1π/12)

  =(cosπ/12)^2-(sin1π/12)^2

  =cosπ/6

  =√3/2

2020-03-04 20:32:47

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