来自钱浚霞的问题
(log29)/(log28)=2/3(log23)
(log29)/(log28)=2/3(log23)
1回答
2020-03-04 06:49
(log29)/(log28)=2/3(log23)
(log29)/(log28)=2/3(log23)
log(2,9)=log(2,3^2)=2log(2,3)
log(2,8)=log(2,2^3)=3log(2,2)=3
所以(log2,9)/(log2,8)=2/3(log2,3)