来自康东来的问题
如图,在△ABC中,AC=CD,∠CAB-∠B=30°,则∠BAD等于()A.30°B.22.5°C.10°D.15°
如图,在△ABC中,AC=CD,∠CAB-∠B=30°,则∠BAD等于()
A.30°
B.22.5°
C.10°
D.15°
1回答
2020-03-04 12:11
如图,在△ABC中,AC=CD,∠CAB-∠B=30°,则∠BAD等于()A.30°B.22.5°C.10°D.15°
如图,在△ABC中,AC=CD,∠CAB-∠B=30°,则∠BAD等于()
A.30°
B.22.5°
C.10°
D.15°
设∠BAD=x,则∠CDA=∠x+∠B,
∵AC=CD,
∴∠CAD=∠CDA=x+∠B,
于是∠CAB=∠2x+∠B,
又∠CAB-∠B=30°,
∴2x+∠B-∠B=30°,
解得x=15°.
故选D.