来自冯新的问题
初二下数学分式方程计算题[(x-4)/(x^2-1)]÷[(x^2-3x-4)/(x^2+2x+1)]+(1/x-1)其中x=2√2+1
初二下数学分式方程计算题
[(x-4)/(x^2-1)]÷[(x^2-3x-4)/(x^2+2x+1)]+(1/x-1)
其中x=2√2+1
1回答
2020-03-06 16:22
初二下数学分式方程计算题[(x-4)/(x^2-1)]÷[(x^2-3x-4)/(x^2+2x+1)]+(1/x-1)其中x=2√2+1
初二下数学分式方程计算题
[(x-4)/(x^2-1)]÷[(x^2-3x-4)/(x^2+2x+1)]+(1/x-1)
其中x=2√2+1
[(x-4)/(x^2-1)]÷[(x^2-3x-4)/(x^2+2x+1)]+(1/x-1)
=(x-4)/[(x+1)(x-1)×(x+1)²/[(x-4)(x+1)]+1/(x-1)
=1/(x-1)+1/(x-1)
=2/(x-1)
2/2√2
=√2/2