来自赖淑蓉的问题
证明cos(x+y)cos(x-y)=cos^2(x)-sin^2(y)
证明cos(x+y)cos(x-y)=cos^2(x)-sin^2(y)
1回答
2020-03-08 09:54
证明cos(x+y)cos(x-y)=cos^2(x)-sin^2(y)
证明cos(x+y)cos(x-y)=cos^2(x)-sin^2(y)
令x+y=A,x-y=Bcos(x+y)cos(x-y)=cosAcosBx=(A+B)/2,y=(A-B)/2,代入cos^2(x)-sin^2(y)=cos2(A+B/2)-sin2(A-B/2)=[1+cos(A+B)-1+cos(A
-B)]/2=cosAcosB-sinAsinB+cosAcosB+sinAsinB)/2=cosAcosB所以cos(x+y)cos(x-y)=cos2x-sin2y