来自胡永胜的问题
解方程组:(1)3(x−1)−4(y−4)=05(y−1)=3(x+5)(2)2x−15+3y−24=23x+15−3y+24=0.
解方程组:
(1)
3(x−1)−4(y−4)=05(y−1)=3(x+5)
(2)
2x−15+3y−24=23x+15−3y+24=0.
1回答
2020-03-08 09:59
解方程组:(1)3(x−1)−4(y−4)=05(y−1)=3(x+5)(2)2x−15+3y−24=23x+15−3y+24=0.
解方程组:
(1)
3(x−1)−4(y−4)=05(y−1)=3(x+5)
(2)
2x−15+3y−24=23x+15−3y+24=0.
(1)化简得
3x−4y=−13(1)3x−5y=−20(2)